Question

only intelligent students

Answer 1

1. area of rhombus = 1/2*diagonals

                               =1/2 * 48 * 20 = 480 cm square

Answer 2

Area of Rhombus:
$\frac{1}{2} \times x \times y$
where x and y are the diagonals of Rhombus.
Therefore area of given Rhombus=
$\frac{1}{2} \times 48 \times 20 = 480 {cm}^{2}$
Also, diagonals of a rhombus bisect perpendicularly. Thus, the diagonals divides rhombus into 4 right triangles.
One side of Rhombus will be hypotenuse of one right triangle.
From Pythagoras Theorem,
$(\frac{48}{2} )^{2} + ( \frac{20}{2} ) ^{2} = side^{2} \\ 676 = side ^{2} \\ 26cm = side$
Now, as adjacent sides of rhombus are equal, therefore perimeter of Rhombus =4×side

Perimeter of given rhombus=
$4 \times 26 = 104cm$