Question

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prove that tanA/1+secA-tanA/1-secA=2cosecA

Answer 1

(tanA/ 1+secA) - (tanA/ 1-secA)
={tanA(1-secA) - tanA(1+secA)} / (1-sec^2A)
={tanA(1-secA-1-secA)} / (-tan^2A)
=(-2secA)/ (-tanA)
=2 (1/cosA) / (sinA/cosA)
=2 (1/sinA)
=2cosecA

Answer 2

hope this will help u