Only maths aryabhatta and brainly rankers solve this question .
Factorise : x^2-0.04 .
Answers
Answer:
hey mate here is your answer
Step-by-step explanation:
x2=(4/100)
Two solutions were found :
x = 1/5 = 0.200
x = -1/5 = -0.200
Reformatting the input :
Changes made to your input should not affect the solution:
(1) "0.04" was replaced by "(04/100)".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x^2-((4/100))=0
Step by step solution :
Step 1 :
Simplify 1/25
Equation at the end of step 1 :
(x^2) - 1/25 = 0
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using 25 as the denominator :
x^2 = x^2/1 = x^2 × 25/25
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x^2×25-(1)/25 = 25x^2-1/25
Trying to factor as a Difference of Squares :
2.3 Factoring: 25x2 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Check : 25 is the square of 5
Check : 1 is the square of 1
Check : x2 is the square of x1
Factorization is : (5x + 1) • (5x - 1)
Equation at the end of step 2 :
(5x+1) × (5x-1) / 25 = 0
Step 3 :
When a fraction equals zero :
3.1 When a fraction equals zero
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now, to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
(5x+1) × (5x-1) / 25 × 25 = 0 × 25
The equation now takes the shape :
(5x+1) • (5x-1) = 0
Theory - Roots of a product :
3.2 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
3.3 Solve : 5x+1 = 0
Subtract 1 from both sides of the equation :
5x = -1
Divide both sides of the equation by 5:
x = -1/5 = -0.200
Solving a Single Variable Equation :
3.4 Solve : 5x-1 = 0
Add 1 to both sides of the equation :
5x = 1
Divide both sides of the equation by 5:
x = 1/5 = 0.200
Two solutions were found :
x = 1/5 = 0.200
x = -1/5 = -0.200
Hope it helps you ✌️✌️✌️✌️
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Answer:
thankyou brother for help ......