Question

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Answer 1

Step-by-step explanation:

Class Interval Frequency midpoint (x) Comm f.

0-6 4 3 4

6-12 x 9 4+x

12-18 5 15 9+x

18-24 y 21 9+x+y

24-30 1 27 10+x+y

Total 20

∑f=20

x+y=10−−−−−−−−−−(1)

Median is 14.4

S0, Median class is 12−18

Median =L+

f

2

n

−C

×w

So 14.4=12+

5

2

20

−(4+x)

×6

14.4×5=60+(10−4−x)×6

72=60+60−24−6x

6x=120−24−72

6x=120−96

6x=24

x=4

from eq (1)

4+y=10⇒y=6