Question

only moderator can solve e part

Answer 1

let's name it first ...
ABC is a ∆ consisting 2 angles one 20 and second 50 and let D be angle 30 and x be E

now draw a line parallel to BD{ Angle B = 50 and D = 30}
let AC be transversal ..
so angle c = angle x [ alternate angles ]

finding ane C by angle sum property
In ∆ABC
angle ( A + B + C ) = 180°
20°+50°+ C = 180
angle C = 110°

hence x = 110°

Answer 2

•See Attachment

Find  ∠DCE:

Exterior angle of a triangle is the sum of the opposite interior angles

∠DCE =  ∠CAB +  ∠ABC

∠DCE = 50 + 20 = 70º

Find x:

Exterior angle of a triangle is the sum of the opposite interior angles

∠BDE = ∠DCE + ∠CED

∠BDE = 70 + 30 = 100º

x = 100º

Answer: x = 100º