Only Moderators will answer
A wire of resistance 10 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the ends of any diameter of the circle?
Answers
Answered by
190
Given :-
- Resistance of wire = 10Ω
To Find :-
- The effective resistance between the two points at the end of any diameter of the circle = ?
Solution :-
- To calculate the effective resistance between the two points at the ends of any diameter of the circle. At first we have to notice on the given clue in the question. As you can see A wire of resistance 10Ω is bent in the form of circle. It means the connection of wire will be parallel . The parallel connection of wire will be the diameter of Bending circle and the radius of bending circles is the 1/2 of the diameter of Bending circle. Simply by applying formula to calculate effective resistance between two points.
Calculation begins.
⇒Radius of bending circle = 1/2 of Diameter
⇒Radius of bending circle = 10/2 = 5Ω
- Effective resistance is calculated when the wire of connection is parallel.
⇒Effective resistance = R_(1) × R_(2)/R_(1) + R_(2)
- R_(1) = 5Ω R_(2) = 5Ω
⇒R_(eff) = 5 × 5/5 + 5
⇒R_(eff) = 25/10
⇒R_(eff) = 2.5Ω
Hence,
- The effective resistance = 2.5Ω
Attachments:
Answered by
60
Given :-
A wire of resistance 10 ohm is bent in the form of a closed circle.
To Find :-
What is the effective resistance between the two points at the ends of any diameter of the circle?
Solution :-
Diameter = 2 × Radius
10 = 2 × Radius
10/2 = Radius
5 = r
We know that
1/Rp = 1/R1 + 1/R2
1/Rp = 1/5 + 1/5
1/Rp = 1 + 1/5
1/Rp = 2/5
Rp = 5/2
Rp = 2.5 Ω
Similar questions
Business Studies,
15 days ago
Science,
15 days ago
CBSE BOARD X,
1 month ago
Math,
1 month ago
Science,
9 months ago