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A wire of resistance 10 ohm is bent in the form of a closed circle. What is the effective resistance between the two points at the ends of any diameter of the circle?​

Answers

Answered by mddilshad11ab
190

Given :-

  • Resistance of wire = 10Ω

To Find :-

  • The effective resistance between the two points at the end of any diameter of the circle = ?

Solution :-

  • To calculate the effective resistance between the two points at the ends of any diameter of the circle. At first we have to notice on the given clue in the question. As you can see A wire of resistance 10Ω is bent in the form of circle. It means the connection of wire will be parallel . The parallel connection of wire will be the diameter of Bending circle and the radius of bending circles is the 1/2 of the diameter of Bending circle. Simply by applying formula to calculate effective resistance between two points.

Calculation begins.

⇒Radius of bending circle = 1/2 of Diameter

⇒Radius of bending circle = 10/2 = 5Ω

  • Effective resistance is calculated when the wire of connection is parallel.

⇒Effective resistance = R_(1) × R_(2)/R_(1) + R_(2)

  • R_(1) = 5Ω R_(2) = 5Ω

⇒R_(eff) = 5 × 5/5 + 5

⇒R_(eff) = 25/10

⇒R_(eff) = 2.5Ω

Hence,

  • The effective resistance = 2.5Ω
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Answered by Itzheartcracer
60

Given :-

A wire of resistance 10 ohm is bent in the form of a closed circle.

To Find :-

What is the effective resistance between the two points at the ends of any diameter of the circle?​

Solution :-

Diameter = 2 × Radius

10 = 2 × Radius

10/2 = Radius

5 = r

We know that

1/Rp = 1/R1 + 1/R2

1/Rp = 1/5 + 1/5

1/Rp = 1 + 1/5

1/Rp = 2/5

Rp = 5/2

Rp = 2.5 Ω

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