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$\huge\underline{Question}$
5.6 liters of methane gas is ignited in oxygen oxygen gas. Calculate the mass of CO2 formed.​

Answer 1

Answer:

0.25 moles of CO2

Explanation:

The combustion of methane is:

CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g)

From this equation, we understand 1 mole of CH4(g) produces 1 mole of CO2(g).

By Avogadro's law, 1 mole of gas at constant pressure and temperature occupies 22.4 L of volume.

Hence, 22.4 L of CH4(g) produces 1 mole of CO2(g).

Then, 5.6 L of CH4(g) produces

5.6/22.4 = 0.25 moles of CO2(g).

Answer 2

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ᴛʜᴇ ᴇϙᴜᴀᴛɪᴏɴ ғᴏʀ ᴛʜᴇ ʀᴇᴀᴄᴛɪᴏɴ:

ᴄʜ 4 + 2ᴏ2 → ᴄᴏ2 + 2ʜ2ᴏ

ᴀᴛ s.ᴛ.ᴘ., 1 ᴍᴏʟ ᴏғ ɢᴀs = 22.4 ʟ

sᴏ, 22.4 ʟ ᴏғ ᴄʜ4 ᴡɪʟʟ ɢɪᴠᴇ 22.4ʟ ᴏғ ᴄᴏ2

⇒ 1ʟ ᴏғ ᴄʜ4 ᴡɪʟʟ ɢɪᴠᴇ 1ʟ ᴏғ ᴄᴏ2

⇒ 5.6ʟ ᴏғ ᴄʜ4 ɢɪᴠᴇs 5.6ʟ ᴏғ ᴄᴏ2

ᴀᴛ s.ᴛ.ᴘ.

22.4ʟ = 1 ᴍᴏʟ

⇒ 5.6 ʟ = 5.6/22.4= 0.25 ᴍᴏʟ

ᴛʜᴜs, 5.6ʟ ᴏғ ᴍᴇᴛʜᴀɴᴇ ᴡɪʟʟ ɢɪᴠᴇ 0.25 ᴍᴏʟ ᴏғ ᴄᴀʀʙᴏɴ ᴅɪᴏxɪᴅᴇ

Explanation:

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