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Find area of the triangle whose two sisides are 8cm and 11cm and perimeter is 32cm.
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Step-by-step explanation:
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Step-by-step explanation:
Two side's of the triangle = 8cm and 11cm
It's perimeter = p = 32cm
Let two sides AB = 8cm and BC = 11cm
Perimeter of the triangle = AB + B.C. + CA
32 = 8 + 11 + CA
32 = 19 + CA
32 - 19 = CA
13 = CA
Therefore, Area of the triangle = A = 1 / 2 × base × height
= 1 / 2 × 13 × 8
= 13 × 8 / 2 = 13 × 4 = 52 square cm.
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