Question

Only one question of algebraic identity

Answer 1

Hey!!!

Here's ur answer



By identity (a+b+c)² = a² + b² + c² + 2ab + 2bc + 2ca
We get,
(x)² + (3/4y)² + (-4z)² + 2(x)(3/4y) + 2(3/4y)(-4z) + 2(-4z)(x)
= x² + 9/16y² + 16z² + 3/2xy - 6yz - 8zx


This is answer


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Answer 2

hey Lusfa

here is your answer

as per rule
$(x + \frac{3}{4}y - 4z) ^{2}$
$will \: equal \: to$
$x ^{2} + (\frac{3} {4y})^{2} - 4z^{2}$

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