Question

only question 7 plzzz
Fast​

Answer 1

Answer:

x³+bx²+cx+d/6 is the third zero.

Step-by-step explanation:

Given,

(3+√3) & (3-√3) are the zeros of the polynomial x³+bx²+cx+d.

Then,

(3+√3)(3-√3) is the factor of p(x)=x³+bx²+cx+d.

Or 6 is the factor of p(x)=x³+bx²+cx+d.

For the third zero,

we need to divide p(x)=x³+bx²+cx+d by 6.

So, x³+bx²+cx+d/6 is the third zero.