Question

only reply if you know the answer, and please with method​

Answer 1

Answer:

let one complementary angle = x

other complementary angle = x + 10

So,

x + x + 10° = 90°

2x + 10° = 90°

2x = 90° - 10°

2x = 80°

x = 80°

2

x = 40°

Then,

first angle = 40°

second angle = x + 10°

= 40° + 10°

= 50°

Answer 2

Answer:

1. let one of the complementary angle be x

then other= x+10

sum of complementary angles = 90

so

x+x+10=90

2x+10=90

2x=80

x=80/2

x=40

x+10=40+10=50

hence the angles are 40° and 50°

2. In triangle PQR

PQ=PR

so angle Q=angle R

angle P=30°

sum of all the angles of a triangle=180°

angle P+angleQ+angle R=180

30+ 2(angle P)=180 (PQ=QR)

angle P=75°

so angle R= angle P= 75°

3. let the ratios be 2x,3x and 5x

sum of all the angles =180°

so

2x+3x+5x=180

10x=180

x=180/10

x= 18

the angles are

2x=2×18=36°

3x=3×18=54°

5x=5×18=90°

It is a right angled triangle

4. angle ACB=180-angleACD

ACB=180-115

ACB= 65

angle A= 180-(65+65)

angle A= 180-130

angle A=50

Hope it helps you!

good evening