Question

Only Right answers please
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Answer 1

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HERE IS UR ANSWER

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• magnitude of resultant vector

${r}^{2} = {a}^{2} + {b}^{2} + 2ab \cos\theta \\ {r}^{2} = {3}^{2} + {4}^{2} + 2(3)(4) \cos(90\degree) \\ {r}^{2} = 9 + 16 + 2(3)(4)(0) \\ {r}^{2} = 9 + 16 = 25 \\ r = √25 = 5units$

resultant =5 units

• Direction of resultant vector

$\tan( \alpha ) = \frac{b \sin(\theta) }{a + b \cos(\theta) } \\ \tan( \alpha ) = \frac{4(1)}{3 + 4(0)} = \frac{4}{3}$

so,from above calculations

option b) is correct

$\large{\bold{\blue{\sf{thanks}}}}$