Question

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Answer 1

Given that Raghav buys a shop for 120000.

He pays half of the amount in cash = 1/2 * 120000

                                                           = 60000.


Balance amount to be paid = 120000 - 60000 = 60000.

Given that amount of each installment = 5000.

He agrees to pay the balance in 12 annual installments with interest of 12%.

1. Amount of the first installment = 5000 + 12/100 * 60000

                                                      = 5000 + 600 * 12

                                                      = 5000 + 7200

                                                      = 12200.


2. Amount of the second installment = 5000 + 12/100 * (60000 - 5000)

                                                             = 5000 + 12/100 * 55000

                                                            = 5000 + 550 * 12

                                                             = 5000 + 6600

                                                             = 11600.


So. the amount paid for installment is 12200,11600.......It forms an AP.

The 1st term a = 12200

Common Difference d =  11600 - 12200

                                     = -600.

The number of terms n = 12.

We know that sum of n terms = n/2(2a + (n-1)* d)

 Therefore the total cost of the shop = 60000 + 12/2(2(12200) + (12-1) * (-600))

                                                              = 60000 + 6(24400 - 6600)

                                                              = 60000 + 6 * 17800

                                                              = 60000 + 106800

                                                              = 166800.


The total cost of the shop = 166800.

Hope this helps!
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Answer 2

this is the answer I hope it will help you