Question

only tell me(x,xi)part

Answer 1

x)36(p+q)^2-64(p-q)^2
=[6(p+q)]^2-[8(p-q)]^2
=[6(p+q)+8(p-q)][6(p+q)-8(p-q)]
=(6p+6q+8p-8q)(6p+6q-8p+8q)
=(14p-2q)(14q-2p)
xi)p^4-(p+q)^4
=[p^2+(p+q)^2][p^2-(p+q)^2]
=[p^2+(p+q)^2][p+p+q][p-p-q]
=[p^2+(p+q)^2](2p+q)(-q)

Answer 2

X ) 36(p + q)^2 -64(p -q )^2

=>{6(p + q)}^2-{8(p - q)}^2

use formula ,
a^2 - b^2 = (a + b)( a - b)

=>{6( p + q)-8( p - q) }{ 6(p + q)+8( p -q )}

=>(6p+6q-8p+8q)(6p+6q+8p-8q)

=>(14q-2p)(14p-2q)

=>4(7q-p)(7p-q)


Xi) p^4 -(p + q)^4

{p^2 -(p + q)^2}{p^2+(p+q)^2}

(p-p-q)(p+p+q)(p^2+p^2+q^2+2pq)

(-q)(2p+q)(2p^2+q^2+2pq)