Only that question I didn't found the answer, please answer my question
Attachments:
Answers
Answered by
2
Sec 40 × sin50 + cos 50 cosec 40
=> sec 40 × cos ( 90 - 40) + sin( 90 - 40) cosec 40
=> sec 40 cos 40 + sin 40 cosec 40
=> cos 40/ Cos 40 + sin40 / sin 40
=> 1 + 1 = 2
=> sec 40 × cos ( 90 - 40) + sin( 90 - 40) cosec 40
=> sec 40 cos 40 + sin 40 cosec 40
=> cos 40/ Cos 40 + sin40 / sin 40
=> 1 + 1 = 2
9OCT2003:
I'm also in standard 10th and I didn't knew the ans for this question
okay
Similar questions