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Case 1 = .1 M CH3COOH
2.706=ixCxRXT
from here i¹=1.1
also i=1+a
a1=.1
Now conc. of CH3COO- =Ca1= .1x.1=.01
Now conc of H+ =Ca1=.1x.1=.01
Case 2 = .2M CH3COOH
5.166=i²XRXCT
from here i²=1.05
Also i²=1+a2
from here a2=.05
Now conc of CH3COO- =Ca2=.2X.05=.01
Now conc of H+ = Ca2=.2X.05=.01
Comparing both cases
- degree of dissociation decrease
- pH of both is same
- Conc of CH3COO- IS SAME
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