Question

Only the brainliest can solve this. Try if you are brainliest.
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Answer 1

$number \: of \: circle = \frac{35}{4} \times \frac{4}{5} = 7 \\ wastage \: aluminium \: \\= ar \: of \: aluminium \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - area \: of \: 7 \: circle \\ = \frac{5}{4} \times \frac{35}{4} - \frac{22}{7} \times \frac{25}{16}$

×7

Answer 2

Answer:

7 circles can be cut with 2.3515625$cm^{2}$ waste

Step-by-step explanation:

Diameter = $1\frac{1}{4}$

Radius = $\frac{5}{8}$

Pi = 3.14...

$8\frac{3}{4}$ / $1\frac{1}{4}$  = (35/4) x (4/5) = 7

$\pi$$r^{2}$= 3.14 x 0.390625 = 1.2265625 = area of 1 circle

1.2265625 x 7 = 8.5859375 = area of 7 circles

$8\frac{3}{4}$ x $1\frac{1}{4}$ = $10\frac{15}{16}$ = 10.9375 = area of aluminum strip

10.9375 - 8.5859375 = 2.3515625 = aluminum wastage