Question

only the branliest can solve my problem
(note: if you cannot solve it then you are a loser )
it my challenge ,let's see who can do it.
Q)., suppose 2+√3 ,1-i are roots of equation (2x^2+px+1)(x^2-2x+q) =0 ,where p,q are integers and i=√-1 then p+q is ​

Answer 1

Maybe this the answer

If wrong than i will edit and give u other answer

Here is your answer

Given ,

one root of quadratic equation 2x² - px + q = 0 is 2 + √3

then, other root must be (2 - √3)

Now, sum of roots = -coefficient of x/coefficient of x²

(2 + √3) + (2 - √3) = -(-p)/2

⇒ 4 = p/2

⇒p = 8

product of roots = constant/Coefficient of x²

(2 + √3)(2 - √3) = q/2

⇒(2² - √3²) = q/2

⇒ 4 - 3 = q/2

⇒ 1 = q/2

⇒q = 2

∴ pq = 8 × 2 = 16 , your options are wrong . Answer should be 16

Thanks

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