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See the above attached attachment....
a = 26°
b = 46°
c = 26°
d = 106°
Hope it helps...
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Answer:
angle PQS + angle SQR = 180 (linear pair)
154 + angle SQR = 180
angle SQR = 26
c = 26
angle SQR = angle TSQ (interior alternate angles; TS is parallel to PR)
Therefore, c = a = 26
angle UST + angle TSQ + angle QSR = 180 (angle formed on a straight line)
48 + 26 + angle QSR = 180
angle QSR = 106
d = 106
In triangle QSR,
angle SQR + angle QRS + angle RSQ = 180 (angle sum property)
26 + 106 + angle SRQ = 180
angle SRQ = 48
b = 48
HOPE THAT IT WAS HELPFUL!!!!
MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!
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