Math, asked by Justalearner, 1 year ago

Only the or part of Q. 31.
Pls solve both the question. Urgent

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Answered by sandipmishra1977
0

Answer:

I will answer both questions of 31

1)Given:A triangle ABC

To prove:angle A+angle B+angle C=180

Construction:Draw a line DAE||BC

Proof:DAE||BC & AB is transversal

hence,angle DAB(4)=angle ABC(2)

DAE||BC &AC is transversal

hence,angle EAC(5)=angle ACB(3)

Now,4+5+angle BAC(1)=180 (DAE is a straight line)

=)2+3+1=180

hence, it is proved that the sum of all angles of triangle is 180

2) Since,AM is the inspector of angle BAM.

angle BAM=angle CAM

In triangle ABN, angle ANB=90

Hence, angle ABN+angle BAN=90

angle ABN=(90-angle BAN)

angle B=(90-angle BAD) (2)

SIMILALY,angle C=(90-angle CAN) (3)

On subtracting ( 3) from (2)

angle B-angle C=(90-BAN)-(90-CAN)

=CAN-BAN

=(CAN+NAM)-(BAN-NAM)

=2NAM

Hence,angle NAM=1/2×(B-C)

Bro, Mark it as Brainlist answer,I need it

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