Math, asked by nights9, 9 months ago

only the ticked questions in this exercise solve​

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Answered by AakritiDutta27
3

AnS:

Q.1 (ii) Solve

x - y = 6 and xy = 16

Then : (x-y)² = (16)²

x² - 2xy = 256

x² + y² = 256 + 2xy

= 256 + 2(16)

= 256 + 32

= 288 ans

Q.3 (i) Doing cube both side

( x + 1/x)³ = (3)³ = 27

x³ + 1/x³ + 3* x * 1/x (x + 1/x) =27

x³ + 1/x³ + 3*3 = 27

x³ + 1/x³ = 27 -9

x³ + 1/x³ = 18

Q.3 (iii) Solve : If x - 1/x = 4 , find x² + 1/x²

= ( x - 1/x )² - ( 1/x)² + 2(x) + (1/x)

= (4)² = x² + 1/x² + 2

= 16 = x² + 1/x² + 2

= x² + 1/x² = 16-2 = 14

Q.4) Solve :

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