only toppers can answer this......
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Pls mark it as the brainliest
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Step-by-step explanation:
(a-b)^3=a^3-b^3-3a^b+3ab^2
now
(a^2-b^2)^3=a^6-b^6-3(a^4)b^2+3a^2b^4
(b^2-c^2)^3=b^6-c^6-3b^4c^2+3c^4b^2
(c^2-a^2)^3=c^6-a^6-3c^4a^2+3a^4c^2
a^6-b^6-3a^4b^2+3a^2b^4+b^6-c^6-3b^4c^2+3c^4b^2+c^6-a^6-3c^4a^2+3a^4c^2
=-3a^4b^2-3b^4c^2-3c^4a^2+3a^2b^4+3c^4b^2+3c^2a^4
=3a^4(c^2-b^2)+3b^4(a^2-c^2)+3c^4(b^2-a^2))
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