Question

only toppers can answer this


who answer this for points they are real #​

Answer 1

Answer:

0

Step-by-step explanation:

Since, |f(y)−f(x)|2≤(x−y)3

⇒ |f(y)−f(x)|2(y−x)2≤(x−y)

⇒ ∣∣∣f(y)−f(x)y−x∣∣∣2≤x−y …(i)

⇒ limy→x∣∣∣f(y)−f(x)y−x∣∣∣2≤limy→x(x−y)

⇒ |f'(x)|2≤0

which is only possible, if |f'(x)|=0

∴f'(x)=0

or f'(x) = Constant