Question

ono
Problem 1. A car of mass 2x10 ³kg travelling at
36km /hr
horizonlal road
& brought to rest
in a distance of
50m by the action of break and
frictional forces calculat (a ) avarage
stopping forces. (b] Time taken to stop the car
​

Answer 1

36 km/hr = 10 m/s

v² = u² + 2as

=> (0)² = 10² + 2×50×a

=> 100a = -100

=> a = -1 m/s²

So, average force = ma = 2 × 10³ × (-1) = -2 × 10³ N

Answer 2

Explanation:

HERE'S YOUR ANSWER.....

(a) Stopping force = -2×10^3

(b) Time taken = 10 sec