Question

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A bullet moving with a speed of 150 m/s strikes a tree and penetrates 3.5
cm before stopping. The magnitude of acceleration and time takes to stop​

Answer 1

Explanation:

find the magnitude of its acceleration and the time taken to stop. A) 32.14 X 10^5 m/s^2 , 4.67 X 10^4 s B) 13.214 X 10^5 ...

Answer 2

u = 150m/s

v = 0m/s (Bullet comes to rest)

S = 3.5cm = 0.035m

a = ?

v² - u² = 2aS

0² - 22500 = 2×a×0.035

a = -22500/0.07 = -32142m/s²

Here, -ve sign indicates that the body is retarding

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