Question

Oooye solve krdo plzzzz...


(23) wala

Bhagwan ache no. Dilayega....

Answer 1

a= w^2 x

20= w^2 (5)

4 = w^2

w= 2

Answer 2

Heya mate,

Here is your answer,. ⬇️⬇️

${ANSWER :-}$
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$<i>$ Here, we have,

Acceleration (a) = 20 cm/s^2.

And, distance from mean position(x) = 5 cm.

Now, value of angular frequency = w

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Now, by condition, we have,

w^2 * x = a

Or, w^2 * 5 = 20

Or, w^2 = 4

Or, w = 2.

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➡️ Hence, the value of angular frequency will be 2 radians/sec.

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$<b>$ Hope this helps,.

If helps, please mark it as brainliest ^_^

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REGARDS, ARNAB ✌️

THANK YOU