oose the correct answer:
G.C.D of (a-4)⁴,(b+c)³,(c-a)power 7
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First expression = a2b + a2c
= a2(b + c)
= a × a × (b + c)
Second expression = (ab + ac)2
= (ab + ac) (ab + ac)
= a(b + c) a(b + c)
= a × a × (b + c) × (b + c)
It can be seen that, in both the expressions ‘a’, ‘a’ and ‘(b + c)’ are the common factors and there is no other common factor.
Therefore, the required H.C.F. is a × a × (b + c) = a2(b + c).
may be this may help you
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