OP bisects angle AOC, OQ bisects angle BOC. OP is perpendicular to OQ. Prove that A, O , B are collinear.
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Since OP is the bisector of ∠AOC
∴∠AOP=∠COP [1]
Since OQ is the bisector of ∠BOC
∴∠BOQ=∠COQ [2]
Now consider ∠AOB
=∠AOP+∠COP+∠COQ+∠BOQ
=∠COP+∠COP+∠COQ+∠COQ
frm[1] and [2]
=2[∠CoP+∠COQ]
=2∠POQ
=2(90°)
∴OP⊥OQ=180°
thus we can say that A,O and B lies on the same line {linear pair}
Hope it is helpful
∴∠AOP=∠COP [1]
Since OQ is the bisector of ∠BOC
∴∠BOQ=∠COQ [2]
Now consider ∠AOB
=∠AOP+∠COP+∠COQ+∠BOQ
=∠COP+∠COP+∠COQ+∠COQ
frm[1] and [2]
=2[∠CoP+∠COQ]
=2∠POQ
=2(90°)
∴OP⊥OQ=180°
thus we can say that A,O and B lies on the same line {linear pair}
Hope it is helpful
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