OP,OQ,OR and OS are four rays Prove that Angle POQ + Angle QOR + Angle SOR + Angle POS =360°
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Solution:-
you need to produce any of the rays OP,OQ,OR or OS. backwards to a point. let's produce a ray OQ backwards to a point T so that TOQ is a line .
Now ray OP stands on the line TOQ .
⠀∴ ⠀⠀⠀⠀⠀∠TOP + ∠SOQ = 180 (1)
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀(linear pair )
Similarly ray OS stands on line TOQ.
∴⠀⠀⠀⠀⠀⠀⠀ ∠TOS + ∠ SOQ = 180° (2)
but ⠀⠀⠀⠀⠀ ∠SOQ = ∠SOR + ∠QOR
So (2) becomes :-
⠀⠀⠀⠀⠀⠀∠TOS + ∠SOR + ∠QOR =180°
Now adding (1) and (2) we get :-
∠TOP + ∠POQ + ∠TOS + ∠SOR + ∠QOR ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀=360°
But ⠀⠀⠀⠀⠀⠀ ∠TOP + ∠TOS = ∠POS
Therefore it becomes :-
∠POQ + ∠QOR+ ∠SOR + ∠POS = 360°
Hence proved √
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