Question

OP perpendicular AB in the image of the central circle on the side If AB = 6 cm and PC = 2 cm, what is the radius of the circle?​

Answer 1

Answer:

Given, AB = 6cm, PC = 2cm

AP

Perpendicular from the center of the circle to any Chord bisects it in two line segments

⇒ AP

⇒ AP = 3cm

⇒ OA = OC

⇒ OA = OP + CP ………..(1)

In

OAP, Using Pythagoras Theorem

OA2 = OP2 + AP2

⇒ (OP + PC)2 = OP2 + 9 (from eq.(1))

⇒ OP2 + PC2 + 2(OP)(PC) = OP2 + 9

⇒ PC2 + 2(OP)(PC) = 9

⇒ 4 + 2(OP)(2) = 9

⇒ 2(OP)(2) = 5

⇒ OP

Radius = OC = OP + PC

⇒ OC = 2 +

⇒ OC = 2.25cm

Answer 2

Step-by-step explanation:

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