open area of a house is in the shape of a trapezium with parallel sides of lengths 12 m and 8 m. perpendicular distance between the parallel sides is 5 metres.find the cost of the paving the open area at the rate of ₹42 per square metre
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Answer:
₹ 2100
Step-by-step explanation:
Area of Trapezium= ½ x (Sum of Parallel Sides) x h
= ½ x (12+8) x 5
= ½ x 20 x 5
= 50m²
Rate of paving per m²= ₹42
Cost of paving 50 m²= 42 x 50
= ₹2100
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