Open area of a house is in the shape of a trapezium with parallel sides in the ratio 3 : 5. Its area is 80 m² and the perpendicular distance between the parallel sides is 5 m. Find the length of two parallel sides of that open area.
Answers
Answer:
Given:
The open area of a house is in the shape of a trapezium with parallel sides in the ratio 3:5.
Its area of 50 m² and the perpendicular distance between the parallel sides is 5m
To find:
Find the length of two parallel sides of the open area.
Solution:
Let's assume "3x" & "5x" are two parallel sides of the trapezium-shaped open area of the house.
The area of the trapezium-shaped open area = 50 m²
The perpendicular distance between the parallel sides i.e., h = 5m
We know the formula of the area of a trapezium is as follows:
Now, on substituting the given values in the formula above, we get
∴ 3x = 3 × 2.5 = 7.5 m
∴ 5x = 5 × 2.5 = 12.5 m
Thus, the length of two parallel sides of the open area of the house is → 7.5 m and 12. 5 m.
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Step-by-step explanation:
Answer:
Given:
The open area of a house is in the shape of a trapezium with parallel sides in the ratio 3:5.
Its area of 50 m² and the perpendicular distance between the parallel sides is 5m
To find:
Find the length of two parallel sides of the open area.
Solution:
Let's assume "3x" & "5x" are two parallel sides of the trapezium-shaped open area of the house.
The area of the trapezium-shaped open area = 50 m²
The perpendicular distance between the parallel sides i.e., h = 5m
We know the formula of the area of a trapezium is as follows:
Now, on substituting the given values in the formula above, we get
\implies 50 = 4x\times 5⟹50=4x×5
∴ 3x = 3 × 2.5 = 7.5 m
∴ 5x = 5 × 2.5 = 12.5 m
Thus, the length of two parallel sides of the open area of the house is → 7.5 m and 12. 5 m.