Question

#OPEN CHALLENGE
Let me see who answers this question correctly
The correct answer with step by step explanation will be marked as BRAINLIEST​

Answer 1

Here is the answer -

Let X be the no. of mangoes.

From the question, we get:-

X = 2a+1

X = 3b+2

X = 4c+3

X = 5d+4

X = 6e+5

And, at last X = 7f

By adding 1 to both sides:-

X + 1 = 2a +1 +1 = 2a+2 = 2(a+1)

X + 1 = 3b + 2 + 1 = 3b+ 3 = 3(b+1)

Similarly, we can find :-

X +1 = 4(c+1)

X + 1 = 5(d+1)

X + 1 = 6(e+1)

X + 1 = 7f + 1

By this we get that when 1 is added to that no. , then it is divisible by 3, 4, 5 and 6.

We egnore least no. 59 as 59 + 1 = 60 is not divisible by 7.

The second last no. divisible by all of these :- 3, 4, 5 and 6 is 120.

So, the no. that is X + 1 should be 120y where y is any positive integer.

We should take least value of y so that X + 1 = 120.

X = 120 - 1

= 119

Therefore, 119 is your answer.

Hope it helped you.