Math, asked by Flexobrainia, 11 months ago






Open the above picture to see my question. To see more details look at my description below or check the original website where I found the question.

It is called Bricsmath and if you log in the first task is my question.

This is a 3x3 box. This has a preset number 1 in it. All the other numbers have to be used only once. Th final answer should be 49. How do I get it?​

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Answers

Answered by amitnrw
1

*2 * 3  + (3 + 5) * 5  +  2 + 1 = 49

((1 + 3 )* 5 + 2 ) * 2 + 5 = 49

Step-by-step explanation:

one Solution :

*2 * 3  + (3 + 5) * 5  +  2 + 1 = 49

2 * 3 = 6

(3 + 5) = 8

= 6 + 8 *5  + 2 + 1

8 * 5 = 40

= 6 + 40 + 2 + 1

= 49

Another Solution :

((3 + 1 )* 5 + 2 ) * 2 + 5 = 49

= ( 4 * 5 + 2) * 2 + 5

= (20 + 2) *2 + 5

= 22 * 2 + 5

= 44 + 5

= 49

https://brainly.in/question/13111006

Answered by FelisFelis
1

Answer:

The required steps are shown below:

Step-by-step explanation:

Consider the provided pink stone.

Steps to solve the problem.

Step 1: Drag the pink stone to +3 that will gives you 1+3=4

Step 2: Drag the pink stone to ×5 that will gives you 4×5=20

Step 3: Drag the pink stone to +2 that will gives you 20+2=22

Step 4: Drag the pink stone to ×2 that will gives you 22×2=44

Step 5: Drag the pink stone to +5 that will gives you 44+5=49

Which is the required expression.

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