Open vessel from the top is in the shape of a frustum our school if the diameters of the upper and lower circular ends of the frustum be 14 cm and 26 CM respectively the height of the frustum is 8 cm
A find the curved surface area of the vessel
B find the capacity of The vessel
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A.C.S.A OF vessel =CSA OF Frustum
therefore, CSA of Frustum= πl(R+r)
but, l=√Hsq+(R-r)sq=√8sq+(13sq-7sq)
=√64+(169-49)
=√64+120
=√184=13.56Cm.sq
CSA =22/7×13.56(13+7)
=852.34
B.is to attachment
therefore, CSA of Frustum= πl(R+r)
but, l=√Hsq+(R-r)sq=√8sq+(13sq-7sq)
=√64+(169-49)
=√64+120
=√184=13.56Cm.sq
CSA =22/7×13.56(13+7)
=852.34
B.is to attachment
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hackerlol77:
nice one raa
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