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The length of a rectangle is 6 cm less than three times its width. The perimeter
rectangle is 140 cm. Find the dimensions of the rectangle
(by asing matrix inversion method)
Answers
Answered by
4
Answer:
let the breadth of the rectangle be b therefore its length is 3b minus 6 and according to the question perimeter of rectangle 148 metre therefore
2(length+breadth)=148
2(3b-6+b)=148
2(4b-6)=148
4b-6=74
then b= 80/4=20m and length equals to 60 minus 6 equal to 54 answer
Answered by
0
Answer:
Step-by-step explanation:
Let,
length of rectangle= x
width of rectangle= y
according to the question:
=> x=3y-6
we can also write it as
x-3y=6
we also know that:
perimeter of rectangle = 2 (length+width)
140= 2(x+y)
*as 2 is being multiplied with (x+y), if we take it on the other side of =.....it will divide 140
140/2 = x+y
70 = x+y
the equations are:
x -4y = 6
x +y =70
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