Question

Opposite angles of a parallelogram are (2x+30) and (3x+20) . find all angles of a parallelogram

Answer 1

Let the opposite angles are (2x+30) and (3x+20).

A/q (2x+30) + (3x+20) = 180°
[ Angle A + Angle D = 180°]

=> 2x + 30 + 3x + 20 = 180°

=> 5x + 50 = 180°

=> 5x = 180° - 50

=> 5x = 130°

=> x = 130/5

=> x = 26° => Answer

Hope it will helps you✌✌