Question

Opposite angles of a parallelogram are 3x-50 and 4x-80. find x. ​

Answer 1

Answer:

$\huge \mathcal \colorbox{pi}{{ \color{red}{❀PêRfèCt ÀnsWër}}}$

Opposite angel I parallelogram are equal

Hence 3x-2=50-x

3x+x=50+2

4x=52

x=52/4=13

3x-2=3×13–2=39–2=37

Other two angels are 180–37=143

Angels i of parallelogram in order=143, 37, 143 and 37

Answer 2

Answer:

$\frac{410}{7}$

Step-by-step explanation:

Given data:

• Opposite angles of a parallelogram are $3x-50$ and $4x-80$

• As we know, Sum of the opposite angles of a parallelogram $180^{0}$

So,

$3x-50+4x-80=180$

$7x-130=180$

$7x=180+130$

$7x=410$

$x=\frac{410}{7}$

Hence, the value of $x$ is $\frac{410}{7}$.