opposite angles of parallelogram are 3x+5 and 61-x find the measure of four angles
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SolutioN :-
In parallelogram ABCD
→ ∠A = ∠C
→ 61 - x = 3x + 5
→ 3x + x = 61 - 5
→ 4x = 54
→ x = 56/4
→ x = 14
Therefore
→ ∠A = 61 - x
→ ∠A = 61 - 14
→ ∠A = 47°
→ ∠C = ∠A
→ ∠C = 47°
→ ∠A + ∠B = 180°
→ 47° + ∠B = 180°
→ ∠B = 180° - 47°
→ ∠B = 133°
→ ∠D = ∠B
→ ∠D = 133°
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