OPQR is a rhombus whose 3 vertices PQR lie on a circle with center 'O'.if the radius of the circle is 10 cm find the area of the rhombus?
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Answer:
□ OPQR is a Rhombus RO = OP = OR = PQ
(sides of Rhombus)
OQ = R (Radius)
Δ RQO and Δ.QOP are equilateral triangles.
∴
4
3
R
2
+
4
3
R
2
=32
3
4
3
R
2
=32
3
⇒R=8cm
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