Question

OPQR is a rhombus whose three vertics P, Q and R lie on the centre of the circle ⭕. If the radius of the circle ⭕ is 12 cm find the area of the rhombus.

Answer 1

hello friend here is ur ans

plz follow me correctly

firstly given radius is 12cm

then we need to find the area of rhombus


, then we have area of rhombus= 1/2 (d1+d2)


where d1 and d2 are length of diagonals

(then for correct picture of problem im drawing the fig for it so plz refer the attachment

so then from the fig it will be clear that three points lie on circle and one at center

then from figure OQ=r =d======(1) ,. where d is diagonal respectively



then from the fig it will be quitely clear that , the triangles of the rhombus will be equilateral
from the fig the two triangles namely OPQ AND ORQ ARE equilateral

from equation 1 it is clear that two diagonals of rhombus are same as that of radii, where as other two are not, so

the length of other diagonals
= 2×altitude of the triangle ORQ = root 3× r

since we kNow that

area of rhombus= 1/2×d1×d2

hence (1/2) ×r×root3× r = area (from the fig)==(2)



since r=12cm
from equation 2 we have 1 /2×12×root 3×12=

72×root3 cm^2




hope ot hepls u


its too lengthy but plz accommodate it

if u wont get it plz comment on it


above mentioned attachment is given plz see it

Answer 2

Hey mate......

here's ur answer......

Hope it helps ❤️