Question

حدیث سے مراد ہے Option 1 : بات چیت کرنا Option 2 : تبادلہ خیال کرنا Option 3 : بحث کرنا

Answer 1

The fraction is...

\frac{5(x - 3)}{6} - x = 1 - \frac{x}{9}

6

5(x−3)

−x=1−

9

x

Solve the bracket...

\frac{5x - 15}{6} - x = 1 - \frac{x}{9}

6

5x−15

−x=1−

9

x

Take the LCM of denominators...

\frac{5x - 15 - 6x}{6} = \frac{9 - x}{9}

6

5x−15−6x

=

9

9−x

Reduce the denominators to simplest forms and solve the required in numerator...

\frac{ - x - 15}{2} = \frac{9 - x}{3}

2

−x−15

=

3

9−x

By Cross Multiplication...

3( - x - 15) = 2(9 - x)3(−x−15)=2(9−x)

- 3x - 45 = 18 - 2x−3x−45=18−2x

- 3x + 2x = 18 + 45−3x+2x=18+45

- x = 63−x=63

The answer is...

x = - 63x=−63