Question

Option 1 Option 2 Option 3 Option 4 Len
Question31
0.31
In Young's double slit experiment, the distance between
the two slits is 0.1 mm and wavelength of light used is
4x 10-m. If the width of fringe on screen is 4 mm, the
distance between screen and slits is
(1) 0.1 mm
(2) 1 cm
(3)0.1 cm
(4) 1 m
Option 1 Option 2 Option 3 Option 4 Left​

Answer 1

Answer:

β=lambda*D/d

lambda =wavelength given

=4*10^-7

β=4*10^-3

d=0.1mm

4*10^--3=4*10^-7*D/0.1*10^-3

D=0.4*10^-6/4*10^-7

=0.1*10^1

=1m