optional find the area of an isosceles triangle whose sides are ab is equal to AC is equal to 4 cm BC is equal to 5 cm
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area of ∆ABC=√s(s-a)(s-b)(s-c)
s=a+b+c÷2
s=4+4+5÷2
s=6.5
area of ∆ABC=√6.5(6.5-4)(6.5-4)(6.5-5).
=√6.5×2.5×2.5×1.5
=√65/10×25/10×25/10×15/10
=1/10√65×25×25×15
=1/10√5×13×5×5×5×5×5×3
=1/10×5×5×5√13×3
=1/10×125√39
=125/10√39
=12.5√39
s=a+b+c÷2
s=4+4+5÷2
s=6.5
area of ∆ABC=√6.5(6.5-4)(6.5-4)(6.5-5).
=√6.5×2.5×2.5×1.5
=√65/10×25/10×25/10×15/10
=1/10√65×25×25×15
=1/10√5×13×5×5×5×5×5×3
=1/10×5×5×5√13×3
=1/10×125√39
=125/10√39
=12.5√39
tanu816:
actually there is a mistake the answer will be 1.25√39
and sorry for the mistake
make it again for me ok
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