Question

options: 360 240 120 None of these

Answer 1

Hola bruh

Your answer is 240

The explanation:

Number of words formed by BHARAT =  $\frac{6!}{2!}$ = 360

Number of words in B and H are together = $\frac{5!}{2!} \times 2$ = 120

Number of letters in which B and H are not together = 360 - 120 = 240

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Answer 2

Answer:

The answer is 240

Step-by-step explanation:

Total number of letters = 6

in which letter "A" in repeated

twice

∴ no of different words formed= 6!/2! = 360

now, when B and H are together,

, then we get S letters (in which again "A"

in repeated twice) which can

be arranged in  5!/2! ways

Also, B and H can be arranged

in 2! ways in them selves )

∴ no of arrangements with B and H

together =  5!/2! ×2!=120ways

So Number of words in which B and H are never together

= Total number of words − Number of words in which

B and H are never together is

360−120=240

therefore = 240