options are-
a. 30
b. 20
c. 40
d. 60
Please solve this and then answer..............
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yuvi walked along length and breadth
➡️distance walked by yuvi =70m
distance walked by heena =50m
yuvi walked 20m more than heena
➡️distance walked by yuvi =70m
distance walked by heena =50m
yuvi walked 20m more than heena
Answered by
3
✌️✌️HOLA MATEY..✌️⭐⭐
There you go .....
Since, it is given that , the length = 40 m
and the breadth = 30 m
By , Pythagoras theorem, we get...
Let, the hypotenuse(diagonal) be x,
30^2 + 40^2 = hypotenuse ^2
=>900 + 1600 = x^2
=>2500 = x^2
=> x = √2500
=> x = 50.
Therefore, the diagonal = 50m
Given, that Hena walked diagonally, therefore, the distance travelled by Hen = 50 m
and,
Distance traveled by Yuvi = 30+40 = 70m
Therefore, Distance travelled by Yuvi is,
70-50 = 20 m more, than Hena.
Thankyou ...✌️⭐
There you go .....
Since, it is given that , the length = 40 m
and the breadth = 30 m
By , Pythagoras theorem, we get...
Let, the hypotenuse(diagonal) be x,
30^2 + 40^2 = hypotenuse ^2
=>900 + 1600 = x^2
=>2500 = x^2
=> x = √2500
=> x = 50.
Therefore, the diagonal = 50m
Given, that Hena walked diagonally, therefore, the distance travelled by Hen = 50 m
and,
Distance traveled by Yuvi = 30+40 = 70m
Therefore, Distance travelled by Yuvi is,
70-50 = 20 m more, than Hena.
Thankyou ...✌️⭐
siku45:
wow
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