OR
2 men and 5 women can together finish a piece of work in 4 days, while 3 men and 6
women can finish it in 3 days. Find the time taken by 1 man alone to finish the work.
Answers
Answer:
Let the work done by man and woman per day be x and y respectively.
When the work is completed in 4 days
Since 5 men and 2 women complete the work in 4 days
therefore work done by 5 men and 2 women in 1 day =
4
1
∴5x+2y=
4
1
⟶eq
n
1
When the work is completed in 3 days
Since 6 men and 3 women complete the work in 3 days
therefore work done by 6 men and 3 women in 1 day =
3
1
∴6x+3y=
3
1
⟶eq
n
2
Multiplying by 3 in eq
n
1, we get
⇒15x+6y=
4
3
⟶eq
n
3
Multiplying by 2 in eq
n
2, we get
⇒12x+6y=
3
2
⟶eq
n
4
On subtracting eq
n
4 from eq
n
3, we get
⇒15x+6y−12x−6y=
4
3
−
3
2
⇒3x=
12
1
⇒x=
36
1
On substituting the value of x in eq
n
2, we get
⇒6×
36
1
+3y=
3
1
⇒3y=
3
1
−
6
1
⇒y=
18
1
Thus,
work done by 1 man in 1 day =
36
1
days
∴ Time taken by 1 man alone to finish the work =36 days
work done by 1 woman in 1 day =
18
1
days
∴ Time taken by 1 woman alone to finish the work =18 days
Answer:
Let the number of days taken by a woman and a man be x and y
According to the question,
⇒ 4(2/x + 5/y) = 1
⇒ 2/x + 5/y = 1/4
⇒ 3(3/x + 6/y) = 1
⇒ 3/x + 6/y = 1/3
Putting 1/x = p and 1/y = q in these equations, we get
⇒ 2p + 5q = 1/4
By cross multiplication, we get
⇒ p/-20 - (-18) = q/-9 - (-18) = 1/144b- 180
⇒ p/-2 = q/-1 = 1/-36
⇒ p/-2 = - 1/36 and q/-1 = 1/-36
⇒ p = 1/18 and q = 1/36
⇒ p = 1/x = 1/18 and q = 1/y = 1/36
⇒ x = 18 and y = 36
Number of days taken by a woman = 18
Number of days taken by a man = 36
Step-by-step explanation: