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ABCs an isosceles triangle, in which AB = AC. circumscribed about a circle. Show that BC is bisected at the point
of contact
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Given:
- ABC is an isosceles triangle in which AB = AC
To Show:
- BC is bisected at the point of contact
Proof:
AX = AY (i)
BX = BZ (ii)
CZ = CY (iii)
(Trangent from external point of circle are equal)
AB = AC (Given)
AX + XB = AY + YC
XB = YC
BZ = CZ
Hence Proved!!
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