Question

OR
ABCs an isosceles triangle, in which AB = AC. circumscribed about a circle. Show that BC is bisected at the point
of contact​

Answer 1

Given:

• ABC is an isosceles triangle in which AB = AC

To Show:

• BC is bisected at the point of contact

Proof:

AX = AY (i)

BX = BZ (ii)

CZ = CY (iii)

(Trangent from external point of circle are equal)

AB = AC (Given)

AX + XB = AY + YC

XB = YC

BZ = CZ

$\therefore \sf \: Z \: is \: mid \: point \: of \: BC \: and \: \\ \sf \: Z \: is \: the \: point \: of \: contact$

Hence Proved!!