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Determine, graphically, the vertices of the triangle formed by the lines represented by 3x - y = 3, 2x - 3y = 2 and x + 2y = 8.
Answers
Answer:
=> 3x-y=3 ------------(1)
=> 2x-3y=2 ----------(2)
=> x+2y=8 ------------(3)
multiply equation (1) by 3 and the subtract equation (2) from it
=> 9x-3y-2x+3y=9-2
=> 7x=7
=> x=1
putting the value of x in (1) we get
3-y=3
y=0
so, one vertex of triangle is (1,0) equation (2) - 2 x equation (3)
=> 2x-3y-2x-4y=2-16
=> -7y= -14
divide both side by 7 , we get
=> y=2
putting the value of y in equation (3) we get
=> x+2y=8
=> x+2*2=8
=> x+4=8
=> x=8-4
=> x=4
The second vertex is (4,2)
2x equation (1)+equation 3 gives
=> 6x-2y+x+2y=6+8
=> 7x=14
dividing both side by 2 we get
=> x=2
putting the value of x in (3) , we get
=> 2+2y=8
=> 2y=8-2
=> 2y=6
=> y=3
the third vertex is (2,3)
We can find the solution is graphically also