Question

Or
Find a relation between x and y such that the
point (x, y) is equidistant from the points
(7, 1) and (3,5).

ansear = x-y=2​

Answer 1

Let P(x,y) be equidistant from the points A(7,1) and B(3,5).

AP=BP

AP

2

=BP

2

(x−7)

2

+(y−1)

2

=(x−3)

2

+(y−5)

2

x

2

−14x+49+y

2

−2y+1=x

2

−6x+9+y

2

−10y+25

x−y=2

Answer 2

X1= 7. x2=3. y1= 1. y2=5

x=(x1+x2)/2. y=(y1+y2)/2

x=5. y=3